Optimal. Leaf size=1059 \[ \text{result too large to display} \]
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Rubi [A] time = 2.51227, antiderivative size = 1047, normalized size of antiderivative = 0.99, number of steps used = 6, number of rules used = 4, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.129, Rules used = {581, 459, 365, 364} \[ -\frac{\left (-c^2 \left (48 B c+A d \left (m^3+(6 p+23) m^2+\left (12 p^2+92 p+183\right ) m+8 p^3+92 p^2+366 p+513\right )\right ) b^3+a c d \left (2 A d \left (m^3+4 (p+5) m^2+\left (4 p^2+44 p+123\right ) m+8 p^2+84 p+216\right )+B c \left (m^3+(4 p+21) m^2+\left (4 p^2+44 p+143\right ) m+4 p^2+40 p+267\right )\right ) b^2-a^2 d^2 (m+5) \left (A d (m+3) (m+2 p+9)+2 B c \left (m^2+2 p m+13 m+2 p+30\right )\right ) b+a^3 B d^3 \left (m^3+15 m^2+71 m+105\right )\right ) \left (b x^2+a\right )^{p+1} (e x)^{m+1}}{b^4 e (m+2 p+3) (m+2 p+5) (m+2 p+7) (m+2 p+9)}+\frac{B \left (b x^2+a\right )^{p+1} \left (d x^2+c\right )^3 (e x)^{m+1}}{b e (m+2 p+9)}+\frac{(6 b B c-a B d (m+7)+A b d (m+2 p+9)) \left (b x^2+a\right )^{p+1} \left (d x^2+c\right )^2 (e x)^{m+1}}{b^2 e (m+2 p+7) (m+2 p+9)}+\frac{\left (c \left (24 B c+A d \left (m^2+4 (p+5) m+4 p^2+40 p+99\right )\right ) b^2-a d \left (A d (m+5) (m+2 p+9)+B c \left (m^2+2 (p+9) m+2 p+65\right )\right ) b+a^2 B d^2 \left (m^2+12 m+35\right )\right ) \left (b x^2+a\right )^{p+1} \left (d x^2+c\right ) (e x)^{m+1}}{b^3 e (m+2 p+5) (m+2 p+7) (m+2 p+9)}-\frac{\left (c \left (2 b^2 (p+3) (a B (m+1)-A b (m+2 p+9)) c^2-2 a b d (p+3) (a B (m+1)-A b (m+2 p+9)) c+b (b c-a d) (m+1) (a B (m+7)-A b (m+2 p+9)) c+\frac{2 b (p+2) (2 b c (p+3) (a B (m+1)-A b (m+2 p+9))+(b c-a d) (m+1) (a B (m+7)-A b (m+2 p+9))) c}{m+1}-a d (b c-a d) (m+1) (a B (m+7)-A b (m+2 p+9))+4 a (b c-a d) (6 b B c-a B d (m+7)+A b d (m+2 p+9))\right )-\frac{a \left (-c^2 \left (48 B c+A d \left (m^3+(6 p+23) m^2+\left (12 p^2+92 p+183\right ) m+8 p^3+92 p^2+366 p+513\right )\right ) b^3+a c d \left (2 A d \left (m^3+4 (p+5) m^2+\left (4 p^2+44 p+123\right ) m+8 p^2+84 p+216\right )+B c \left (m^3+(4 p+21) m^2+\left (4 p^2+44 p+143\right ) m+4 p^2+40 p+267\right )\right ) b^2-a^2 d^2 (m+5) \left (A d (m+3) (m+2 p+9)+2 B c \left (m^2+2 p m+13 m+2 p+30\right )\right ) b+a^3 B d^3 \left (m^3+15 m^2+71 m+105\right )\right )}{b (m+2 p+3)}\right ) \left (b x^2+a\right )^p \left (\frac{b x^2}{a}+1\right )^{-p} \, _2F_1\left (\frac{m+1}{2},-p;\frac{m+3}{2};-\frac{b x^2}{a}\right ) (e x)^{m+1}}{b^3 e (m+2 p+5) (m+2 p+7) (m+2 p+9)} \]
Antiderivative was successfully verified.
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Rule 581
Rule 459
Rule 365
Rule 364
Rubi steps
\begin{align*} \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^3 \, dx &=\frac{B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^3}{b e (9+m+2 p)}+\frac{\int (e x)^m \left (a+b x^2\right )^p \left (c+d x^2\right )^2 \left (-c (a B (1+m)-A b (9+m+2 p))+(6 b B c-a B d (7+m)+A b d (9+m+2 p)) x^2\right ) \, dx}{b (9+m+2 p)}\\ &=\frac{(6 b B c-a B d (7+m)+A b d (9+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b^2 e (7+m+2 p) (9+m+2 p)}+\frac{B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^3}{b e (9+m+2 p)}+\frac{\int (e x)^m \left (a+b x^2\right )^p \left (c+d x^2\right ) \left (-c (2 b c (3+p) (a B (1+m)-A b (9+m+2 p))+(b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p)))+(-2 b c d (3+p) (a B (1+m)-A b (9+m+2 p))-d (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))+4 (b c-a d) (6 b B c-a B d (7+m)+A b d (9+m+2 p))) x^2\right ) \, dx}{b^2 (7+m+2 p) (9+m+2 p)}\\ &=\frac{\left (a^2 B d^2 \left (35+12 m+m^2\right )+b^2 c \left (24 B c+A d \left (99+m^2+40 p+4 p^2+4 m (5+p)\right )\right )-a b d \left (A d (5+m) (9+m+2 p)+B c \left (65+m^2+2 p+2 m (9+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^3 e (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{(6 b B c-a B d (7+m)+A b d (9+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b^2 e (7+m+2 p) (9+m+2 p)}+\frac{B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^3}{b e (9+m+2 p)}+\frac{\int (e x)^m \left (a+b x^2\right )^p \left (-c \left (2 b c (2+p) (2 b c (3+p) (a B (1+m)-A b (9+m+2 p))+(b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p)))+(1+m) \left (2 b^2 c^2 (3+p) (a B (1+m)-A b (9+m+2 p))-2 a b c d (3+p) (a B (1+m)-A b (9+m+2 p))+b c (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))-a d (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))+4 a (b c-a d) (6 b B c-a B d (7+m)+A b d (9+m+2 p))\right )\right )-\left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right ) x^2\right ) \, dx}{b^3 (5+m+2 p) (7+m+2 p) (9+m+2 p)}\\ &=-\frac{\left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^4 e (3+m+2 p) (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{\left (a^2 B d^2 \left (35+12 m+m^2\right )+b^2 c \left (24 B c+A d \left (99+m^2+40 p+4 p^2+4 m (5+p)\right )\right )-a b d \left (A d (5+m) (9+m+2 p)+B c \left (65+m^2+2 p+2 m (9+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^3 e (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{(6 b B c-a B d (7+m)+A b d (9+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b^2 e (7+m+2 p) (9+m+2 p)}+\frac{B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^3}{b e (9+m+2 p)}-\frac{\left (c \left (2 b c (2+p) (2 b c (3+p) (a B (1+m)-A b (9+m+2 p))+(b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p)))+(1+m) \left (2 b^2 c^2 (3+p) (a B (1+m)-A b (9+m+2 p))-2 a b c d (3+p) (a B (1+m)-A b (9+m+2 p))+b c (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))-a d (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))+4 a (b c-a d) (6 b B c-a B d (7+m)+A b d (9+m+2 p))\right )\right )-\frac{a (1+m) \left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right )}{b (3+m+2 p)}\right ) \int (e x)^m \left (a+b x^2\right )^p \, dx}{b^3 (5+m+2 p) (7+m+2 p) (9+m+2 p)}\\ &=-\frac{\left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^4 e (3+m+2 p) (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{\left (a^2 B d^2 \left (35+12 m+m^2\right )+b^2 c \left (24 B c+A d \left (99+m^2+40 p+4 p^2+4 m (5+p)\right )\right )-a b d \left (A d (5+m) (9+m+2 p)+B c \left (65+m^2+2 p+2 m (9+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^3 e (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{(6 b B c-a B d (7+m)+A b d (9+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b^2 e (7+m+2 p) (9+m+2 p)}+\frac{B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^3}{b e (9+m+2 p)}-\frac{\left (\left (c \left (2 b c (2+p) (2 b c (3+p) (a B (1+m)-A b (9+m+2 p))+(b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p)))+(1+m) \left (2 b^2 c^2 (3+p) (a B (1+m)-A b (9+m+2 p))-2 a b c d (3+p) (a B (1+m)-A b (9+m+2 p))+b c (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))-a d (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))+4 a (b c-a d) (6 b B c-a B d (7+m)+A b d (9+m+2 p))\right )\right )-\frac{a (1+m) \left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right )}{b (3+m+2 p)}\right ) \left (a+b x^2\right )^p \left (1+\frac{b x^2}{a}\right )^{-p}\right ) \int (e x)^m \left (1+\frac{b x^2}{a}\right )^p \, dx}{b^3 (5+m+2 p) (7+m+2 p) (9+m+2 p)}\\ &=-\frac{\left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^4 e (3+m+2 p) (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{\left (a^2 B d^2 \left (35+12 m+m^2\right )+b^2 c \left (24 B c+A d \left (99+m^2+40 p+4 p^2+4 m (5+p)\right )\right )-a b d \left (A d (5+m) (9+m+2 p)+B c \left (65+m^2+2 p+2 m (9+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^3 e (5+m+2 p) (7+m+2 p) (9+m+2 p)}+\frac{(6 b B c-a B d (7+m)+A b d (9+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b^2 e (7+m+2 p) (9+m+2 p)}+\frac{B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^3}{b e (9+m+2 p)}-\frac{\left (c \left (2 b c (2+p) (2 b c (3+p) (a B (1+m)-A b (9+m+2 p))+(b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p)))+(1+m) \left (2 b^2 c^2 (3+p) (a B (1+m)-A b (9+m+2 p))-2 a b c d (3+p) (a B (1+m)-A b (9+m+2 p))+b c (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))-a d (b c-a d) (1+m) (a B (7+m)-A b (9+m+2 p))+4 a (b c-a d) (6 b B c-a B d (7+m)+A b d (9+m+2 p))\right )\right )-\frac{a (1+m) \left (a^3 B d^3 \left (105+71 m+15 m^2+m^3\right )-a^2 b d^2 (5+m) \left (A d (3+m) (9+m+2 p)+2 B c \left (30+13 m+m^2+2 p+2 m p\right )\right )+a b^2 c d \left (2 A d \left (216+m^3+84 p+8 p^2+4 m^2 (5+p)+m \left (123+44 p+4 p^2\right )\right )+B c \left (267+m^3+40 p+4 p^2+m^2 (21+4 p)+m \left (143+44 p+4 p^2\right )\right )\right )-b^3 c^2 \left (48 B c+A d \left (513+m^3+366 p+92 p^2+8 p^3+m^2 (23+6 p)+m \left (183+92 p+12 p^2\right )\right )\right )\right )}{b (3+m+2 p)}\right ) (e x)^{1+m} \left (a+b x^2\right )^p \left (1+\frac{b x^2}{a}\right )^{-p} \, _2F_1\left (\frac{1+m}{2},-p;\frac{3+m}{2};-\frac{b x^2}{a}\right )}{b^3 e (1+m) (5+m+2 p) (7+m+2 p) (9+m+2 p)}\\ \end{align*}
Mathematica [A] time = 0.445544, size = 248, normalized size = 0.23 \[ x (e x)^m \left (a+b x^2\right )^p \left (\frac{b x^2}{a}+1\right )^{-p} \left (\frac{c^2 x^2 (3 A d+B c) \, _2F_1\left (\frac{m+3}{2},-p;\frac{m+5}{2};-\frac{b x^2}{a}\right )}{m+3}+d x^4 \left (d x^2 \left (\frac{(A d+3 B c) \, _2F_1\left (\frac{m+7}{2},-p;\frac{m+9}{2};-\frac{b x^2}{a}\right )}{m+7}+\frac{B d x^2 \, _2F_1\left (\frac{m+9}{2},-p;\frac{m+11}{2};-\frac{b x^2}{a}\right )}{m+9}\right )+\frac{3 c (A d+B c) \, _2F_1\left (\frac{m+5}{2},-p;\frac{m+7}{2};-\frac{b x^2}{a}\right )}{m+5}\right )+\frac{A c^3 \, _2F_1\left (\frac{m+1}{2},-p;\frac{m+3}{2};-\frac{b x^2}{a}\right )}{m+1}\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.072, size = 0, normalized size = 0. \begin{align*} \int \left ( ex \right ) ^{m} \left ( b{x}^{2}+a \right ) ^{p} \left ( B{x}^{2}+A \right ) \left ( d{x}^{2}+c \right ) ^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B x^{2} + A\right )}{\left (d x^{2} + c\right )}^{3}{\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (B d^{3} x^{8} +{\left (3 \, B c d^{2} + A d^{3}\right )} x^{6} + 3 \,{\left (B c^{2} d + A c d^{2}\right )} x^{4} + A c^{3} +{\left (B c^{3} + 3 \, A c^{2} d\right )} x^{2}\right )}{\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B x^{2} + A\right )}{\left (d x^{2} + c\right )}^{3}{\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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